If x is 12% of 180, then what is the value of 7x ?

I need help with this. What is the answer?

e-lub [12.9K]

Answer:

The answer is 30 because that triangle is a right triangle which is 90 degrees and then divide it by 3

Step-by-step explanation:

8 0

3 years ago

What is 30% of 50 pounds?

Morgarella [4.7K]

Answer:

15 pounds

Step-by-step explanation:

hope that help

3 0

3 years ago

Read 2 more answers

–2|u| = –68 ill give 5 oints

german

The solution to the given equation –2|u| = –68 is u = 34, -34.

<h3>What is the solution to the equation?</h3>

Given the equation in the question;

–2|u| = –68

To find u, divide both sides by -2

–2|u| = –68

(–2|u|)/2 = (–68)/-2

|u| = 34

Remove the absolute value term, this create ± on the right side of the equation. ( |x| = ±x )

u = ±34

Hence,

u = 34, -34

Therefore the solution to the given equation –2|u| = –68 is u = 34, -34.

Learn more about absolute values here: brainly.com/question/1301718

#SPJ1

8 0

1 year ago

Hurry!!!Need help with this question!!! If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*h)(x)?

nignag [31]

Hey there,

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*h)(x)?

Based on my understanding, I believe that your correct answer would
be 2x2 – 16x + 30 because 2x^2-16x+30. Just by plugging in both 2x^2
and also 16x+30, so this would mean that 2x²-16x+30 would be your correct answer.

Hope this helps.

4 0

2 years ago

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

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Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago