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stealth61 [152]
2 years ago
5

What is 100,203 in expanded form.

Mathematics
2 answers:
Andru [333]2 years ago
6 0
100,203 in expanded form:

100 + 200 + 3





slega [8]2 years ago
3 0
100,000+ 200+3=100,203
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RUDIKE [14]
2 square root 51 or 14.28
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2 years ago
What is y in the first line if the line passing though (-1,y) and (1,0) perpendicular to the line passing (8,4) and (-1,1) ?
malfutka [58]

Answer:

6.

Step-by-step explanation:

A line that goes through (x_{0},\, y_{0}) and (x_{1},\, y_{1}) where x_{0} \ne x_{1} would have a slope of m = (x_{1} - x_{0}) / (y_{1} - y_{0}).

The slope of the line that goes through (8,\, 4) and (-1,\, 1) would thus be:

\begin{aligned}m_{2} &= \frac{1 - 4}{(-1) - 8} \\ &= \frac{(-3)}{(-9)} \\ &= \frac{1}{3}\end{aligned}.

Two lines in a cartesian plane are perpendicular to one another if and only if the product of their slopes is (-1).

Thus, if m_{1} and m_{2} denote the slope of the first and second lines in this question, m_{1}\, m_{2} = (-1) since the two lines are perpendicular to one another. Since m_{2} = (1/3), the slope of the first line would be:

\begin{aligned} m_{1} &= \frac{(-1)}{m_{2}} \\ &= \frac{(-1)}{(1/3)} \\ &= (-3)\end{aligned}.

Given that the first line goes through the point (1,\, 0), the point-slope equation of that line would be:

(y - 0) = (-3)\, (x - 1).

y = -3\, x + 3.

Substitute in x = (-1) to find the y-coordinate of the point in question:

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2 years ago
Condense log₂ 4 + log₂ 5
yawa3891 [41]

Answer:   \log_2(20)

Work Shown:

\log_2(4) + \log_2(5)\\\\\log_2(4*5)\\\\\log_2(20)\\\\

The rule used is \log_{b}(\text{x}) + \log_{b}(\text{y}) = \log_{b}(\text{xy})

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Neko [114]
1 kilo=1000 meters. 
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5000 divided by 1 station every 400 miles.
5000/400=12.5
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<em />I dont know if you're supposed to round but there you go!
8 0
3 years ago
Trigonometric identities assignment 4
kykrilka [37]

Answer:

<em>Answer: choice D.</em>

Step-by-step explanation:

<u>Trigonometric Functions</u>

We need to recall some properties and definitions of the trigonometric functions.

\displaystyle \tan \theta=\frac{\sin\theta}{\cos\theta}

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Operating:

\displaystyle 5\sin\theta\sec\theta=5\frac{\sin\theta}{\cos\theta}

Substituting the definition of the tangent:

\displaystyle 5\sin\theta\sec\theta=5\tan\theta

Correct choice D.

6 0
2 years ago
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