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tangare [24]
3 years ago
6

Solve the simultaneous equation 2x+5y=6 and 5x-2y=9​

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

x = \frac{57}{29} \ , \ y = \frac{12}{29}

Step-by-step explanation:

                            2x + 5y = 6     --------( 1 )

                            5x - 2y = 9     --------( 2 )

                        _____________

     ( 1 ) x 5 =>     10x + 25y = 30   -----------( 3 )

     ( 2 ) x 2 =>    10x - 4y = 18       ----------- ( 4 )

                       ______________

    ( 3 ) - ( 4 ) =>    0 +  29y = 12

                                   y = \frac{12}{29}

Substitute y in ( 1 ) =>

                            2x + (5 \times \frac{12}{29}) = 6\\\\2x + \frac{60}{29} = 6\\\\2x = 6 - \frac{60}{29}\\\\2x = \frac{174 - 60}{29}\\\\x = \frac{114}{29 \times 2}\\\\x = \frac{57}{29}

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What are the zeros of the function below? Check all that apply.
galina1969 [7]

Answer:

x = 3 or x = 2 or x = -1 or x = -5

Step-by-step explanation:

Solve for x:

((x - 3) (x - 2) (x + 1) (x + 5))/x = 0

Multiply both sides by x:

(x - 3) (x - 2) (x + 1) (x + 5) = 0

Split into four equations:

x - 3 = 0 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0

Add 3 to both sides:

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x = 3 or x = 2 or x + 1 = 0 or x + 5 = 0

Subtract 1 from both sides:

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8 0
3 years ago
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QUESTION 9
Ratling [72]
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8 0
3 years ago
What is the equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3?
Alika [10]
<h3><u><em>Option B</em></u></h3><h3><u><em>The equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3</em></u></h3><h3><u><em /></u>y + 3 = \frac{2}{3}(x -5)<u><em /></u></h3>

<em><u>Solution:</u></em>

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y - y_1 = m(x-x_1)

Where, "m" is the slope of line

Given that,

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