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MatroZZZ [7]
2 years ago
6

Calcula de dos maneras diferentes 1) (-12).8 2) 14.(-5).(-11) Porfa

Mathematics
1 answer:
nata0808 [166]2 years ago
8 0

The value of (-12) . 8 is -96 and the value of 14.(-5).(-11) is 770

<h3>How to solve the expressions?</h3>

The question implies that we calculate the expressions in two different ways.

<u>1) (-12).8</u>

<u>Way 1:</u>

We have:

(-12).8

This means

(-12) . 8 = -12 * 8

Evaluate

(-12) . 8 = -96

<u>Way 2</u>

We have:

(-12).8

This means

(-12) . 8 = -12 * 8

Express 8 as 4 + 4

(-12) . 8 = -12 * (4 + 4)

Expand

(-12) . 8 = -12 * 4 -12 * 4

Evaluate the products

(-12) . 8 = -48 - 48

Evaluate the sum

(-12) . 8 = -96

Hence, the value of (-12) . 8 is -96

<u>2) 14.(-5).(-11)</u>

<u>Way 1:</u>

We have:

14.(-5).(-11)

This means

14.(-5).(-11) = 14 * -5 * -11

Evaluate

14.(-5).(-11) = 770

<u>Way 2</u>

We have:

14.(-5).(-11)

This means

14.(-5).(-11) = 14 * -5 * -11

Multiply -5 and -11

14.(-5).(-11) = 14 * 55

Multiply 14 and 55

14.(-5).(-11) = 770

Hence, the value of 14.(-5).(-11) is 770

Read more about products at:

brainly.com/question/10873737

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It is given that the weight of the barbel is given by:

f(x)=20x+10

It says that there are eight pair of weights so x can take values from 0 to 8 and f(x) can take the values as follows:

\begin{gathered} x=0,f(x)=10 \\ x=1,f(x)=30 \\ x=2,f(x)=50 \\ x=3,f(x)=70 \\ x=4,f(x)=90 \\ x=5,f(x)=110 \\ x=6,f(x)=130 \\ x=7,f(x)=150 \\ x=8,f(x)=170 \end{gathered}

So the range is:

\mleft\lbrace10,30,50,70,90,110,130,150,170\mright\rbrace

Option B is correct.

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Answer:

<h2><u><em>125 gal</em></u></h2>

Step-by-step explanation:

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100 + 25 = 125

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Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)

Note that cot(x) = cos(x) / sin(x). Hence:

\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)

Multiply:

\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Split:

\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)

Simplify:

\csc(x)-\sin(x)=\csc(x)-\sin(x)

Problem 2)

We want to verify that:

\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}

Square:

\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}

Factor out the sin²(x) from the denominator:

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Factor (perfect square trinomial):

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Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

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Factor (difference of two squares):

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Factor out a negative from the first factor in the denominator:

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Cancel:

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Distribute the negative into the numerator. Therefore:

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