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2 years ago

Calcula de dos maneras diferentes 1) (-12).8 2) 14.(-5).(-11) Porfa

Mathematics

1 answer:

nata0808 [166]2 years ago

8 0

The value of (-12) . 8 is -96 and the value of 14.(-5).(-11) is 770

<h3>How to solve the expressions?</h3>

The question implies that we calculate the expressions in two different ways.

1) (-12).8

Way 1:

We have:

(-12).8

This means

(-12) . 8 = -12 * 8

Evaluate

(-12) . 8 = -96

Way 2

We have:

(-12).8

This means

(-12) . 8 = -12 * 8

Express 8 as 4 + 4

(-12) . 8 = -12 * (4 + 4)

Expand

(-12) . 8 = -12 * 4 -12 * 4

Evaluate the products

(-12) . 8 = -48 - 48

Evaluate the sum

(-12) . 8 = -96

Hence, the value of (-12) . 8 is -96

2) 14.(-5).(-11)

Way 1:

We have:

14.(-5).(-11)

This means

14.(-5).(-11) = 14 * -5 * -11

Evaluate

14.(-5).(-11) = 770

Way 2

We have:

14.(-5).(-11)

This means

14.(-5).(-11) = 14 * -5 * -11

Multiply -5 and -11

14.(-5).(-11) = 14 * 55

Multiply 14 and 55

14.(-5).(-11) = 770

Hence, the value of 14.(-5).(-11) is 770

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For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2

find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
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areanotcovered=676-530.66=145.34 square inches not coverd

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Answer:

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Step-by-step explanation:

we know that

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That means

1 inch in the model represent 2 feet in the actual

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we know that

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we know that

The model width is described as 5 inches. Both the 3-inch length and the 5-inch width are less than the 8.5 inch and 7 inch dimensions of the paper Kelly is using.

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Do you mean the 5th roots of 1? Or the 5th roots of 1^(1/5), i.e. the 5th roots of the 5th roots of 1?

I assume you mean the former. To begin with,

1 = exp(0°i ) = cos(0°) + i sin(0°)

Take the 5th root, i.e. (1/5)th power of both sides, so that by DeMoivre's theorem,

1^(1/5) = [ cos(0°) + i sin(0°) ]^(1/5)

1^(1/5) = cos((0° + 360°n)/5) + i sin((0° + 360°n)/5)

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• cos(720°/5) + i sin(720°/5) = cos(144°) + i sin(144°)

• cos(1080°/5) + i sin(1080°/5) = cos(216°) + i sin(216°)

• cos(1440°/5) + i sin(1440°/5) = cos(288°) + i sin(288°)

If you wish, or are required to, you can go on to write these in terms of radicals by expanding cos(5x) and sin(5x) (where x = 72° so that 5x = 360°). For example,

cos(5x) = cos⁵(x) - 10 cos³(x) sin²(x) + 5 cos(x) sin⁴(x)

cos(5x) = cos⁵(x) - 10 cos³(x) (1 - cos²(x)) + 5 cos(x) (1 - cos²(x))²

cos(5x) = 16 cos⁵(x) - 20 cos³(x) + 5 cos(x)

which follows from the expansion

(cos(x) + i sin(x))⁵ = cos(5x) + i sin(5x)

due to DeMoivre's theorem and equating the real parts. Then cos(5x) = 1, and you can try to solve for cos(x) :

1 = 16 cos⁵(x) - 20 cos³(x) + 5 cos(x)

Actually, it would be easier to find sin(x) first, since sin(5x) = 0. The expansion in terms of sin(x) will look quite similar to the one shown here.

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