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3 years ago

Please help. im terrible at math.

Mathematics

2 answers:

Naddika [18.5K]3 years ago

4 0

-20 1/12 mixed number

Aleksandr-060686 [28]3 years ago

3 0

Answer:

-20 1/12

Step-by-step explanation:

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Marsha spends 150 minutes a night doing homework.

kodGreya [7K]

Answer:

70%

Step-by-step explanation:

Maths homework takes 1/6×150mins

=150/6=25 mins

science homework takes 20/100×150

=3000/100

=30mins

Language Arts homework uses 1/3×150

=150/3

=50 mins

percent of time left for Marsha's social studies homework=total time used / original time

=(25+30+50)mins

=105mins/150mins×100%

=0.7×100

=70%

3 0

2 years ago

The measure of the two sides of a triangle.

Phoenix [80]

Answer:

Step-by-step explanation:

The answer is A because well 3x would not change and 17x would not change but 7 and 5 would change because they are not variable numbers So when u do the mah you would get 3x2+17x -2

5 0

2 years ago

What is the name of this figure:

nika2105 [10]

Answer:

tringular prism

Step-by-step explanation:

there u go

4 0

3 years ago

I NEED HELP WORTH THIS there is one more option of 6,6 also

grigory [225]

Answer:

C. (2,4)

Step-by-step explanation:

7 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago