I think the plane is a circle right so if its intersect with a three dimensional object and base on the choices that you give where as its a diagram, the shape would be the object with the side of it is focused . I hope you are satisfied with my answer and feel free to ask for more.
so if it was three four hours and he took four five of the time it will be all day for take away for 0/0
Answer:
Consider lining up all the blue marbles and placing one red marble in between them. Let that arrangement be fixed. The remaining red marbles will be 5 red marbles. Note that the arrangement will be:
x BR x BR x BR x BR x BR x BR x BR x B x
Note that this is the same even if our arrangement is
x B x RB x RB x RB x RB x RB x RB x RB x
Note that there are 9 spots, denoted by x, where we can put the 5 remaining red marbles. To find the number of ways of putting the remaining 5 red marbles to x, it is similar in finding the number of non-negative solution for the equation
which is given by
= 1287
Hence, there are 1287 ways of arranging 8 blue marbles and 12 red marbles without placing 2 blue marbles next to each other.
Eleven over 20. It's eleven over 20. They said my answer needs to be more than 20 characters is why I'm continuing writing
Answer:
x = 3, y = 3, z = - 2
Step-by-step explanation:
Given the 3 equations
x - y - 2z = 4 → (1)
- x + 3y - z = 8 → (2)
- 2x - y - 4z = - 1 → (3)
Add (1) and (2) term by term to eliminate x
2y - 3z = 12 → (4)
Multiply (1) by 2 and add to (3) to eliminate x
2x - 2y - 4z = 8 → (5)
Add (3) and (5) term by term to eliminate x
- 3y - 8z = 7 → (6)
Multiply (4) by 3 and (6) by 2
6y - 9z = 36 → (7)
- 6y - 16z = 14 → (8)
Add (7) and (8) term by term to eliminate y
- 25z = 50 ( divide both sides by - 25 )
z = - 2
Substitute z = - 2 into (7)
6y + 18 = 36 ( subtract 18 from both sides )
6y = 18 ( divide both sides by 6 )
y = 3
Substitute y = 3 and z = - 2 into (1)
x - 3 + 4 = 4
x + 1 = 4 ( subtract 1 from both sides )
x = 3
Solution is x = 3, y = 3, z = - 2