I can solve with 2 methods:
I. Because the discount is 15 % of 18 $ , the price will be (100-15=85) 85 % of 18 $
18*85/100= 15,3 $ ( the sale price)
II. The discount is 15 % of 18$
15*18/100= 2,7$ ( the discount)
then I decrease it from the regularly price
18$-2,7$=15,3 $ (the sale price)
Personally I believe the first is an easier method.
I hope you understand and you can apply this in every similary problem.
Initial Conditions:
length=L= 10 cm = (10*10⁻²)m
Diameter=D= 2 cm= (2*10⁻²)m
Radius= r= 0.01m
Area=A= π*r²/2 =1.57*10⁻⁴ m²
Resistance=R= 600 ohm
So, from initial conditions we find resistivity(р)
R=рL/A
R*A /L=р
(600)*(1.57*10⁻⁴)/(10*10⁻²)=р
р=0.942 Ω m
<span>As, material remains same so resistivity(p) doesn't change
</span>Lenght= L1= 15 fm= 15*10⁻¹⁵ m
Diameter= D1 = 5 cm= 5*10⁻² m
Radius= r= 0.025 m
Area= A1= π*r²/2 =9.8125*10⁻⁴ m²
R=р*L1/A1
R=(0.942 )*(15*10⁻¹⁵ )/(9.8125*10⁻⁴)
R=1.44*10⁻¹¹ Ω
Answer:
Option C 
Step-by-step explanation:
we know that
The measurement of the <u>exterior angle</u> is the semi-difference of the arcs it comprises
so
we have
substitute
Rewrite
Answer:
3,6
Step-by-step explanation:
