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2 years ago

Please help me with either one, (all both) I’ve been struggling with this

Mathematics

2 answers:

Sholpan [36]2 years ago

5 0

Answer:

x = 12, x = 7

Step-by-step explanation:

The 2 legs of the triangle are congruent, both 2x + 7, then

2x + 7 + 2x + 7 + x + 11 = 85 ← equation for perimeter

5x + 25 = 85 ( subtract 25 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

-----------------------------------------------------------

Opposite sides are congruent, then

2(2x) + 2(5x + 3) = 104 ← distribute and simplify both sides

4x + 10x + 6 = 104

14x + 6 = 104 ( subtract 6 from both sides )

14x = 98 ( divide both sides by 14 )

x = 7

Ronch [10]2 years ago

5 0

Answer:

x=12 x=7 yup thank me later

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At a local department store, jeans are typically priced at $15. Due to a special, the jeans are reduced to 80% of their original

vodomira [7]

Answer:the price of jeans now is $12

Step-by-step explanation:

Let x represent the current price of the jeans. At the local department store, jeans are typically priced at $15. It means that the original price of the jeans is $15 .

Due to a special, the jeans are reduced to 80% of their original price. This means that the original price was reduced by 20%. Therefore, the current price, x would be

x = 15 - (20/100 × 15) = 15 - 3

x = $12

6 0

3 years ago

Reduce sixteen over twenty four

yawa3891 [41]

16/24 = 4/6 which = 2/3

5 0

2 years ago

Read 2 more answers

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

The angle of elevation of the top of a pole as seen from a point 13 ft away from the base is double its angle of elevation as se

spayn [35]

The height of the pole above the level of the observer's eyes is 31.42 ft

Let the angle of elevation of the top of the pole from a point 47 ft away be α.

Let the angle of elevation of the top of the pole from the point 13 ft away be β.

Since the angle of elevation of a point 13 feet away is twice that from 47 ft away, we have that β = 2α.

If the height of the pole above the level of the observer's eye is h, we have that

tanβ = tan2α = h/13 and tanα = h/47

From trigonometric identities tan2α = 2tanα/(1 - tan²α)

Substituting the values of the variables into the equation, we have

tan2α = 2tanα/(1 - tan²α)

h/13 = 2h/47 ÷ [1 - (h/47)²]

Dividing through by h, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

Cross-multiplying, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

1 - (h/47)² = 2/47 × 13

1 - (h/47)² = 26/47

(h/47)² = 1 - 26/47

(h/47)² = (47 - 26)/47

(h/47)² = 21/47

Taking square-root of both sides, we have

h/47 = √(21/47)

Cross-multiplyng, we have

h = √(21/47) × 47

h = √(21 × 47)

h = √987

h = 31.42 ft

The height of the pole above the level of the observer's eyes is 31.42 ft

Learn more about height of a pole here:

brainly.com/question/10375496

4 0

2 years ago

If the area of a rectangle is 83& and the width of a rectangle is 2&, what is the length of the rectangle?

zepelin [54]

Answer:

l=41.5

Step-by-step explanation:

Using the formula A=wl

l= $\frac{A}{w} }$ = $\frac{83}{2}$ =41.5

5 0

2 years ago