Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).
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It should be noted that a population means the entire group that a researcher wants to draw conclusions about.
<h3>What is a population?</h3>
Your information is incomplete s the data is not provided. Therefore, an overview will be given.
In statistics, a population refers to a set of similar items which is of interest for an experiment.
On the other hand, a sample is a set of individuals or objects that are selected from a statistical population through a defined procedure.
In this case, it is important to deduce if the sample represents the population.
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Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation:
Answer:
CBA is a secant.
Step-by-step explanation:
There are 6720 ways by 8 distinguishable books be placed in 5 shelves.
According to statement
The number of books (n) is 8
The number of shelves (r) is 5
Now, we find the ways by which the 8 books be placed in 5 distinguishable shelves
From Permutation formula
P(n,r) = n! / (n-r)!
Substitute the values then
P(n,r) = 8! / (8-5)!
P(n,r) = (8*7*6*5*4*3*2*1) / (3*2*1)
P(n,r) = 8*7*6*5*4
P(n,r) = 6720
So, there are 6720 ways by 8 distinguishable books be placed in 5 shelves.
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