The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer is A
Triangle UVW ~ Triangle UWT ~ Triangle WVT
Our hint here is the identity of the shape. It is mentioned that the shape is a square. By definition, a square is a two-dimensional with four sides having equal measures. The formula for its area is:
A = s², where s is the length of its side
Substituting the value of A,
25/36 in² = s²
s = √(25/36)
s = 5/6 inches or 0.833 inches
Set up the following equations:
x represents car A's speed, and y represents car B's speed.
We'll use elimination to solve this system of equations. Multiply the first equation by 7:
Combine both equations:
Divide both sides by 28 to get x by itself:
The speed of car A is
80 mph.Since we now know the value of one of the variables, we can plug it into the first equation:
Subtract 160 from both sides.
Divide both sides by 2 to get y by itself:
The speed of car B is
60 mph.
