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2 years ago

Pand Q are points on the line 3x + 2y = 6 (a) Complete the coordinates of P and Q.

Mathematics

1 answer:

Mama L [17]2 years ago

3 0

Answer:

you are multiplying baceicly

Step-by-step explanation:

3×2=6

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miss Akunina [59]

Answer:

Probability that she selects a blue bead

= 3/9

= 1/3

Step-by-step explanation:

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1 year ago

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HELP ASAP GIVING BRANLIST 100 POINTS!!

musickatia [10]

Rate of change = difference in y over difference in x.

Rate of change = (33-20)/(3-1) = 13/2

Rate of change = (48-33) /(5-3) = 15/2

The rates are not the same so it isn’t linear.

The rate of change for x=3 and x = 5 is greater.

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2 years ago

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The scale of a map is 1:1,000,000. What are the real distances between two points if the distance between them on this map is 35

Inessa [10]

35km; Since the points on the map are one millionth of their actual size, simply multiply by one million and convert from there.

35*1,000,000 = 35,000,000mm

35,000,000/1000 = 35,000m

35,000/1000 = 35km

8 0

2 years ago

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Taxi Driver charges a fixed rate of R to pick up a passenger in addition to Taxi Driver charges a rate of M for each mile driven

IRISSAK [1]

Answer:

t=nm+r

Step-by-step explanation:

Since you are trying to find time, represented by t, you set the equation equal to t. Then you need to add n multiplied by miles, m, to the fixed rate, r.

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2 years ago

One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t

Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) $M = \frac{8*3 + 16*5}{3+5}= 13$

c) $M = \frac{8*5 + 16*3}{5+3}= 11$

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

$M = \frac{8*3 + 16*5}{3+5}= 13$

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

$M = \frac{8*5 + 16*3}{5+3}= 11$

7 0

2 years ago