Explanation:
Separately the periods for sin 4x and sin x are
π
2
and
2
π
.
The LCM =
2
π
is the period for the compounded oscillation
y
=
sin
4
x
−
4
sin
x
.
The second not-to-scale graph is for just one period
x
∈
[
−
π
,
π
]
.
graph{sin 4x - 4 sin x [-40, 40, -20, 20]}
graph{sin 4x - 4 sin x [-3.14, 3.14, -6.28, 6.28]}
So it is a 1/26 chance of drawing c first. Then its the same chance for A and same chance for R. You multiply these fractions so the answer is 1/17576. If this is right could you possibly give me brainliest? Hope this helped.
Hi there!
Recall:
d = st, where:
d = distance
s = speed
t = time
We can set up an expression where the extra ten minutes is taken into account:
50x = 65(x - 10) <--- because J left 10 minutes after, we must subtract from the time variable, or "x".
Solve for x:
50x = 65x - 650
Subtract 65x from both sides:
-15x = -650
Divide both sides by -15:
x ≈ 130/3 or 43.33 min
Answer:
The asnwer is 6.37 y
Step-by-step explanation:
You have to add them sum means addition
I hope this helps