It has been proved that the 5 star vertices have their sum of angles as A + B + C + D + E = 180°
<h3>How to find the sum of angles of a polygon?</h3>
The adjoining star contains a regular pentagon. Thus;
Sum of interior angles of the pentagon = (5 - 2) * 180 = 540°
Thus;
Each interior angle of the pentagon = 540/5 = 108°
Thus, each exterior angle = 180 - 108 = 72°
Then measure of the angle at the vertex = 180 - 72 - 72 = 36°
Thus, each angle at the vertices of the star have an angle of 36°.
There are 5 star vertices and so;
Sum of angles of 5 star vertices = 5 * 36 = 180°
Read more about Angles in a Polygon at; brainly.com/question/1592456
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If the two shortest sides of the triangle are 10in and 24in, then using Pythagoras' theorem, the longest side =
=

=

Now we know the two longest sides of the first triangle (24in and 26in) we can compare them with the two longest sides of the second triangle.
If

= the scale factor the first triangle is enlarged by then

and
⇒

Finally, we need to multiply the smallest side of the first triangle by the scale factor to find the shortest side of the second triangle.

So the length of the shortest side of the other triangle is 15in.
You could, instead, calculate the length of the shortest side of the second triangle by using Pythagoras' theorem and ignoring the first triangle completely.
Answer:
4
Step-by-step explanation:
100 = 2*2*5*5
84 = 2*2*3*4
the greatest common factor is a prime number whit most appearance in both numbers:
in this case the prime number is 2 and it is repeated twice in both numbers, hence 2*2 = 4
Answer:
32 divided (10-8) divided by 2-3