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a_sh-v [17]
2 years ago
13

Find the volume. Round to two decimal places if necessary.

Mathematics
1 answer:
Sati [7]2 years ago
6 0

Answer:

Refer to the attachment and Thank U

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3 years ago
What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c
Nastasia [14]

Answer:

(x-2)^2+(y+5)^2=36

Step-by-step explanation:

Recall that the equation of a circle of radius R centered at (x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

For your particular case: R = 6, x_0 = 2, and y_0 = -5, therefore the equation becomes:

(x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36

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3 years ago
Find the distance between the points (4,-2), (4,-5)
kiruha [24]

\text{Given that,}\\\\(x_1,y_1) = (4,-2)~~ \text{and}~~  (x_2 ,y_2) = (4,-5)\\\\\text{Distance} = \sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\\\\~~~~~~~~~~~~=\sqrt{(4-4)^2 + (-5+2)^2}\\\\~~~~~~~~~~~~=\sqrt{0^2+(-3)^2}\\\\~~~~~~~~~~~~=\sqrt{0+9}\\\\~~~~~~~~~~~~=\sqrt 9\\\\~~~~~~~~~~~~=3

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2 years ago
P and q are points on the line 2y-5x=10
schepotkina [342]

Answer:

2y-5x =10\\when \ x = 0,  \ 2y = 10 => y = 5\\\\\\when \ y = 0, -5x =10 => x =-2\\\\Therefore \ the \  coordinates \  of \ the \  points \ p \ and  \ q\   are  \ (0, 2) \ and  \  (-2, 0)

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