3 years ago

Obtain all zeros of x^4-7x^2+12, if two numbers of its zeros are √3 and -√3

Mathematics

1 answer:

iogann1982 [59]3 years ago

4 0

Answer:

Step-by-step explanation:

x^2=u

u^2-7u+12=0

(u-3)(u-4)=0

u=3,4

x^2=3,4

x^2=3

x = ±√3

x^2 = 4

x=±2

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ASAP! Please help me with this question!

Nonamiya [84]

Answer:

24 cm

Step-by-step explanation:

The volume of a sphere is given by

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2304 pi = 4/3 pi r^3

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2304 = 4/3 r^3

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2304 * 3/4 = 4/3 r^3 * 3/4

1728 = r^3

Take the cube root of each side

1728 ^ 1/3 = r^3 ^ 1/3

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Julli [10]

Answer:

x = 2

Step-by-step explanation:

AB/BC = AD/DE

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cross-multiply:

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Find the value of x so that the line passing through the points will have the given slope: (x,6) and (10,-3) with a slope of -3/

Lana71 [14]

$(x,6) \\
x_1=x \\
y_1=6 \\ \\
(10,-3) \\
x_2=10 \\ y_2=-3 \\ \\
\hbox{the slope: } m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-6}{10-x}=\frac{-9}{10-x} \\ \\
m=-\frac{3}{2} \\
\Downarrow \\
-\frac{3}{2}=\frac{-9}{10-x} \\
-\frac{3}{2}(10-x)=-9 \\
10-x=-9 \times (-\frac{2}{3}) \\
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Answer:

Step-by-step explanation:

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