Question

Solve each system of equations algebraically x-y=6 y=-1

Answer 1

Answer:

Therefore, the solution of the system of equations will be:

$x=5,\:y=-1$

Step-by-step explanation:

Given the system of equations

$x-y=6;\:y=-1$

solving

$\begin{bmatrix}x-y=6\\ y=-1\end{bmatrix}$

$\mathrm{Subsititute\:}y=-1$

$\begin{bmatrix}x-\left(-1\right)=6\end{bmatrix}$

$\begin{bmatrix}x+1=6\end{bmatrix}$

Isolate x for $x+1=6$

$x+1=6$

$x=5$

Therefore, the solution of the system of equations will be:

$x=5,\:y=-1$

Answer 2

Answer:

x-(-1)=6

-x=6

-x/-1 6/-1

x=-6