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2 years ago

How many of the first 15 positive integers can be written as the sum of three squares?

Mathematics

1 answer:

Jlenok [28]2 years ago

3 0

Answer

no number from the following list can be expressed as the sum of three squares: 7, 15, 23, 31, 39, 47, ect... so only once

Step-by-step explanation:

nono dont touch me there this is my nono square

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2 years ago

a circle has a radius of 4 an arc in this circle has a central angle of 288 what is the length of the arc

AnnZ [28]

Answer:

20.1 units

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3 years ago

I WILL MARK BRAINLIEST <br><br> 22 - 2x + 4(x - 2)= 34

lara [203]

Answer:

x = 10

Step-by-step explanation:

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--------------------------------

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/2 /2

--------------------------------

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7 0

2 years ago

Read 2 more answers

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

3 years ago