For a cartesian equation

Given r = <span>10 tan(θ) sec(θ)

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
There are 5 ways to test if two figures are congruent, namely;
side-angle-side(SAS)
Angle-side-angle (ASA)
Angle-angle-side(AAS)
Hypotenuse-leg (HL)
3 Sides (SSS)
here we shall focus on SSS. When the three corresponding sides of 2 figures say a triangle have the same length we will conclude that the triangles are congruent by SSS.
Therefore from our choices we can conclude that triangles ABC and ADC are only congruent if the two other side have the same length and BC=DC.
The answer is yes;
B] Yes, but only if BC=DC
Answer: 55.56
Step-by-step explanation:
Let the unknown number be k
(45 x k) / 100 = 25
45k/100 = 25
multiply both sides by 100
45k = 25 x 100
45k = 2500
divide both sides by 45
k = 2500/45
k = 55.56
the answer is true because 6x multiply -2 to give -12x and 6x multiplies x² to give 6x³
There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula
(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4
(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A