3 years ago

What are the discontinuities of the function f(x) = x^2+2x-24/6x+24?

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

a vertical asymptote at x=-4

Step-by-step explanation:

$f(x)=\dfrac{x^2+2x-24}{6x+24}=\dfrac{(x+6)(x-4)}{6(x+4)}$

The binomial denominator factor is not canceled by a numerator factor, so represents a vertical asymptote at x=-4. That is the only discontinuity

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