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KIM [24]
3 years ago
6

Determine the Lateral Area of the cylinder.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer:

i think its 112π ft²

Step-by-step explanation:

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Can somebody help me out with these notes? I had attempted it but I’m not sure if it’s right and I have to show work.
Rudik [331]

Step-by-step explanation:

The +7 is the y-intercept

It is where the line starts in your example and is 7 units away from 0

Since the line is decreasing the 3 is negative

6 0
3 years ago
Helpppppp please find the value of x
snow_tiger [21]

Answer:

48 + 87 + 20x - 10 = 180

125 + 20x = 180

20x = 55

x = 2.75

45 + 48 + 87 = 180

3 0
3 years ago
What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?
spin [16.1K]

Answer:

<h2>A) y = -5x - 8</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (-1, -3). Substitute:

y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)

Convert to the slope-intercept form (y = mx + b):

y+3=-5(x+1)          <em>use the distributive property</em>

y+3=-5x-5            <em>subtract 3 from both sides</em>

y=-5x-8

7 0
4 years ago
A child grew 3 1/4 inches one year and 4 3/4 inches the next year. How many inches did the child grow over the two years?
Marianna [84]

let's firstly convert the mixed fractions to improper fractions, and then use the LCD, which in this case is 4, to sum them up.


\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{4\frac{3}{4}}\implies \cfrac{4\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{19}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{19}{4}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{13+19}{4}}\implies \cfrac{32}{4}\implies 8

5 0
3 years ago
Read 2 more answers
Find the illegal values of b in the fraction (2b^2+36-10)/(b^2-26-8)
skad [1K]
Correct Question is: Find the illegal values of b in the fraction (2b^2 + 3b - 10)/(b^2 - 2b - 8)

illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.

So setting the denominator equal to zero, we can find these values.

b^{2} -2b-8=0 \\  \\ &#10; b^{2}-4b+2b-8=0 \\  \\ &#10;b(b-4)+2(b-4)=0 \\  \\ &#10;(b+2)(b-4)=0 \\  \\ &#10;b=-2, b=4

Thus, b=-2 and b=4 are the illegal values for this expression
6 0
4 years ago
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