Step-by-step explanation:
The +7 is the y-intercept
It is where the line starts in your example and is 7 units away from 0
Since the line is decreasing the 3 is negative
Answer:
<h2>A) y = -5x - 8</h2>
Step-by-step explanation:
The point-slope form of an equation of a line:

m - slope
(x₁, y₁) - point on a line
We have the slope m = -5, and the point (-1, -3). Substitute:

Convert to the slope-intercept form (y = mx + b):
<em>use the distributive property</em>
<em>subtract 3 from both sides</em>

let's firstly convert the mixed fractions to improper fractions, and then use the LCD, which in this case is 4, to sum them up.
![\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{4\frac{3}{4}}\implies \cfrac{4\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{19}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{19}{4}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{13+19}{4}}\implies \cfrac{32}{4}\implies 8](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B13%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B13%7D%7B4%7D%2B%5Ccfrac%7B19%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B13%2B19%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B32%7D%7B4%7D%5Cimplies%208)
Correct Question is: Find the illegal values of b in the fraction
(2b^2 + 3b - 10)/(b^2 - 2b - 8)illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.
So setting the denominator equal to zero, we can find these values.
Thus, b=-2 and b=4 are the illegal values for this expression