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Sergio039 [100]
2 years ago
10

PLZ SOLVE PIC ATTACHED BELOW

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
4 0

Answer:

\tan(51°)  =  \frac{10}{x}  \\x =  \frac{10}{ \tan(51°) }  \\ x = \frac{10}{1.235}  \\ \boxed{ x = 8.1}

<h3>★ Value of x is <u>8.1</u>.</h3>

\sin(51°)=  \frac{10}{H}  \\ h =  \frac{10}{ \sin(51°) }  \\ H=  \frac{10}{0.777}  \\  \boxed{H= 12.8676}

<h3>★ Value of H is <u>12.8676</u>.</h3>

Remember:

  • tan∅=Perpendicular/Base
  • sin∅=Perpendicular/Hypotenuse

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Which of the following is a polynomial?
Tcecarenko [31]

Answer:

(D.) 3x^2 + 6x

Step-by-step explanation:

the other options aren't complete and some don't even create a parabola.

3 0
2 years ago
Subtract 5x - 2 from -3x +4
Solnce55 [7]

Answer:

8x+2

Step-by-step explanation:

Or -8x+2 but i think its 8x+2

4 0
2 years ago
What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300
hodyreva [135]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30

It can be written as

2(\ln 2x)-(\ln 10x)=\ln 30         [\because \ln e^a=a]

\ln (2x)^2-(\ln 10x)=\ln 30        [\because \ln a^b=b\ln a]

\ln \dfrac{4x^2}{10x}=\ln 30        [\because \ln \dfrac{a}{b}=\ln a-\ln b]

\ln \dfrac{2x}{5}=\ln 30

On comparing both sides, we get

\dfrac{2x}{5}=30

Multiply both sides by 5.

2x=150

Divide both sides by 2.

x=75

Therefore, the correct option is B.

7 0
3 years ago
Help only right awnsers same as last one more points
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Answer:

#8. 9 groups

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8 0
2 years ago
I need help, pls !!!
luda_lava [24]

Answer:

D) 11.2 Orange

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (-8, -1)

Point (-3, 9)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    \displaystyle d = \sqrt{(-3+8)^2+(9+1)^2}
  2. Add:                                      \displaystyle d = \sqrt{(5)^2+(10)^2}
  3. Exponents:                           \displaystyle d = \sqrt{25+100}
  4. Add:                                      \displaystyle d = \sqrt{125}
  5. Simplify:                               \displaystyle d = 5\sqrt{5}
  6. Evaluate:                              \displaystyle d = 11.1803
  7. Round:                                 \displaystyle d = 11.2
8 0
2 years ago
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