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Contact [7]
3 years ago
5

Plz answer correctly and I will give you the brainiest answer.

Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

Communtative property of mulitplcation

Step-by-step explanation:

The ansewer is the Communtative property of mulitplcation because it states  That it allows two or more factors to be multiplied in anny order without changing the profit

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Solve the inequality. T/4 > 7
Digiron [165]

Answer:

T>28

Step-by-step explanation:

Multiply 4 to both sides to get your variable alone.

3 0
3 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
3 years ago
A signal light is green for 4 minutes, yellow for 10 seconds, and red for 3 minutes. If you drive up to this light, what is the
posledela

Answer:

0.56 is the required probability.

Step-by-step explanation:

Time for which signal shows green light = 4 minutes

Time for which signal shows yellow light = 10 seconds

Time for which signal shows red light = 3 minutes

To find:

Probability that the signal will show green light when you reach the destination = ?

Solution:

First of all, let us convert each time to same unit before doing any calculations.

Time for which signal shows green light = 4 minutes = 4 \times 60 seconds = 240 seconds

Time for which signal shows yellow light = 10 seconds

Time for which signal shows red light = 3 minutes = 3 \times 60 seconds = 180 seconds

Now, let us have a look at the formula for probability of an event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, E is the event that green light is shown by the signal.

Number of favorable cases mean the time for which green light is shown and Total number of cases is the total time <em>(Time for which green light is shown + Time for which Yellow light is shown + Time for which red light is shown)</em>

So, the required probability is:

P(E) = \dfrac{240}{240+10+180}\\\Rightarrow P(E) = \dfrac{240}{430}\\\Rightarrow \bold{P(E) \approx 0.56 }

5 0
3 years ago
If the speed of a is 3 ft/s up and is increasing at 4 what is the instantaneous speed and acceleration
Tasya [4]
Sorry I'm in high school.. but according to my physics class, the instantaneous speed is when t (time) is 0, or whatever you'd use (like x).. anyways, when t=0, the instantaneous speed would be 3 ft/s, and the instantaneous acceleration is 0.
6 0
3 years ago
I don’t know how to take a picture on this and send it out for a question
Amanda [17]

Answer:

Where it says "add attachment" with the paper clip, select your picture from there. If you don't know how to do that, take a picture of it with your phone, email it to yourself, and download it on your computer. It should then be in a folder called "downloads" or something similar. Feel free to ask further questions if you're still stuck!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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