If net force acting on an object is 0 then the force is considered to be ..

Light travels at a constant speed of 186,000 mi/seg or 300,000km/seg accross the Universe (in vacuum conditions). Radio waves are also part of the electromagnetic spectrum, and they also travel at the same speed as Light does.

A light-year is a measure of the distance that Light travels during a year, that is, 5.88 trillion miles. Light travels the same distance per year because its speed is constant, and this is an excellent property that scientists take advantage to measure distances.

A parsec is 3.26 light-years (19 trillion miles), and (a very important datum to solve this question) one light-year is 0.306601 parsec, that is, in a year Light travels 0.306601 parsec at a constant speed. The same would happen with intelligent radio signals broadcasted from a distant star system.

So, considering all these facts, it is a matter of proportions to solve this question (mostly because speed of Light is constant):

$\frac{1 year}{0.306601 parsec} = \frac{X years}{30 parsecs}$

$x =\frac{1 year * 30 parsec}{0.306601 parsec}$

$x = \frac{30}{0.306601} years$

x = 97.84704 years or,

x = 97.85 years, approximately.

In other words, Light spends 97.85 years (terrestials) to travel 30 parsecs.

Likewise, radio waves travel at the same speed, so they spend the same years (97.85 years) travelling across the Universe to be finally detected by a radiotelescope located, for instance, here, in our planet.

Finally, the star system broadcasted intelligent radio signal with 'news' that are already approximately 97.85 years old'.

6 0

3 years ago

Why is it preferable to code web pages in HTML format?

balu736 [363]

Answer:

its c on plato

Explanation:

5 0

3 years ago

Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find

Gnoma [55]

Answer:

def find_max(num_1, num_2):

max_val = 0.0

if (num_1 > num_2): # if num1 is greater than num2,

max_val = num_1 # then num1 is the maxVal.

else: # Otherwise,

max_val = num_2 # num2 is the maxVal

return max_val

max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

5 0

3 years ago