Answer:
public class Main
{
public static void main(String[] args) {
int carYear = 1995;
if(carYear < 1967)
System.out.println("Probably has few safety features.");
if(carYear > 1971)
System.out.println("Probably has head rests.");
if(carYear > 1992)
System.out.println("Probably has anti-lock brakes.");
if(carYear > 2002)
System.out.println("Probably has tire-pressure monitor.");
}
}
Explanation:
The code is in Java.
Initialize the carYear
Use if statements to handle year before 1967, after 1971, after 1992 and after 2002.
Print the required message for each if statement
Answer and Explanation:
Within the following operating mode, most of the wireless controller remains linked through the main point (access point) for that broader server. The server runs within ad-hoc modes when this does not run under the following mode. Wireless servers wouldn't have the connectivity to interact within ad-hoc mode.
So, the following statement is correct according to the given scenario of the following mode.
Complete Question:
A campus bookstore sells both types and in the last semester sold 56% laptops and 44% desktops. Reliability rates for the two types of machines are quite different, however. In the first year, 5% of desktops require service, while 15% of laptops have problems requiring service.
Given that a computer required service, what is the probability that it was a laptop?
Answer:
Probability = 0.084
Explanation:
Given
Laptops = 56%
Desktop = 44%
Service Required (Laptop) = 15%
Service Required (Desktop) = 5%
Required
Determine the probability that a selected computer is a laptop and it requires service.
The question tests our knowledge of probabilities using "and" condition.
What the question requires is that, we calculate the probability of selecting a LAPTOP that REQUIRES SERVICE
Note the capitalised words.
This will be calculated as follows:
Probability = P(Laptop) and P(Service Required (Laptop))
[Substitute values for P(Laptop) and P(Service Required (Laptop))]
Probability = 56% * 15%
[Convert to decimal]
Probability = 0.56 * 0.15
Probability = 0.084
