The answer for this question is 80
d=-5.5 should be the answer
Hello here is a solution :
<span> midpoint between A and B,is :C( (Xa+xb)/2; (ya+yb)/2)
C( (-1-3)/2;(5-7)/2)
C(-2 ; -1)</span>
Answer:
54
Step-by-step explanation:
Multiply:
<em>37x37=72</em>
<em>Subtract:</em>
<em>180-72=108</em>
<em>Divide:</em>
<em>108/2=54</em>
Answer:
Total number of notes is 11.
Step-by-step explanation:
Value is 100 rupees…
5x + 20y = 100 and x + y = 11 are the two equations.
We can simplify…
5x + 20 y - 5x - 5y = 100 - 55 = 45
15y = 45 so y = 3
x = 11 - y = 8
So, we have 8 notes of 5 rupees denomination and 3 notes of 20 rupees denomination.
I hope it helps you.
