What is the value of y?

a business want to increase its number of employees by 65% to 20,460. How many employees does the company currently have?

Crazy boy [7]

Answer:

12,400

Step-by-step explanation:

Let the current employees be x

65% increase in number = 0.65x

If the total number of employees after the increase is 20,460, then;

x + 0.65x = 20,460

1.65x = 20,460

x = 20,460/1.65

x = 12,400

Hence the current number of employees is 12,400

5 0

3 years ago

20≥8+4.99x please I could get an F.

marin [14]

Answer:

$\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}$

Step-by-step explanation:

$20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}$

5 0

3 years ago

What kind of websites will the search engine blacklist?

Alex777 [14]

Answer:Usually, websites that end up in a blacklist are either hacked, infected with malware or have some irregularities, that Google finds suspicious.

6 0

3 years ago

Read 2 more answers

A random sample of n = 16 professors from a university has been selected; salaries have been plotted on the following Q-Q plot.

Semenov [28]

Answer:

The objective of the confidence interval is to give a range in which the real mean of the population is placed, with a degree of confidence given by the level of significance.

The conclusion we can make is that there is 95% of probability that the mean of the population (professor's average salary) is within $99,881 and $171,172.

Step-by-step explanation:

This is a case in which, from a sample os size n=16, a confidence interval is constructed.

The objective of the confidence interval is to give a range in which the real mean of the population is placed, with a degree of confidence given by the level of significance. In this case, the probability that the real mean is within the interval is 95%.

5 0

3 years ago

At a grocery store the manager randomly selects 20 cartons of eggs, he finds 3 cartons with at least 1 broken egg. If the refrig

ivann1987 [24]

Answer:

You would expect 75 cartons with at least 1 broken egg.

There are likely to be 222 DVD players that are defective.

Step-by-step explanation:

Both examples given in this question represent a ratio of broken or defective to a sample number of cartons or DVD players. In order to find how many would be broken or defective overall, you can set up equivalent ratios, or proportions.

Egg Cartons: $\frac{broken}{#cartons}=\frac{3}{20}=\frac{x}{500}$

'x' represents the number of cartons out of 500 that would be expected to have at least 1 broken egg. To solve for 'x' you can cross-multiply and divide, or you can find what factor you would multiply the denominator by to get 500 and then multiply the same factor by the numerator to find 'x'. In this case 500/20 = 25, so the factor is 25. 3 x 25 = 75, so you have 75 expected cartons with a broken egg.

DVD Players: $\frac{defective}{#players}=\frac{3}{50}=\frac{x}{3700}$

'x' represents the number of DVD players out of 3700 that would be expected to be defective. To solve for 'x' you can cross-multiply and divide, or you can find what factor you would multiply the denominator by to get 3700 and then multiply the same factor by the numerator to find 'x'. In this case 3700/50 = 74, so the factor is 74. 3 x 74 = 222, so you have 22 likely defective DVD players.

4 0

3 years ago