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Klio2033 [76]
3 years ago
9

The point A (−5,4) is reflected over the point (−2,5) and its image is point B. What are the coordinates of point B?

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

<em>The coordinates of B are (1,6)</em>

Step-by-step explanation:

<u>Point Reflection</u>

Given the point P(x,y) and its reflection P'(x',y') with respect to the point C(xc,yc), C is the midpoint of the segment PP'.

This means the coordinates of C are:

\displaystyle x_c=\frac{x+x'}{2}

\displaystyle y_c=\frac{y+y'}{2}

If the coordinates of the midpoint are given, then the endpoint P' can be found solving for x' and y':

x'=2x_c-x

y'=2y_c-y

The point P' is the reflection of P over C.

We are given the coordinates of A(-5,4) and the point (-2,5). We need to find the coordinates of point B(x',y'). Let's use the formulas as if A was point P and C=(-2,5):

x'=2(-2)-(-5)=-4+5=1

y'=2(5)-4=10-4=6

The coordinates of B are (1,6)

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Answer:

B

Step-by-step explanation:

A graph is only a function when there is only one y value for each x value.

A trick is to draw a line through some points on the x-axis, and if the line goes through more than one point. Then it is not a function. (See picture)

Sorry, not all the lines are straight, but you get the point. B is the only one that doesn't have more than one point on the lines I drew.

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3 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
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Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

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Following the steps which I gave, you take 1 value for the y (preferably the larger one) which in this cause will be 2 and then another y from the table which would be 1

Do the same for x

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\frac{2 - 1}{2 - 1}

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