Convert to cylindrical coordinates:



Then
is the set of points
such that
,
, and
or
.
Now

Answer:
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Answer:
I don't know what kind of questions is this but first you need to show your spinner
we know that
the standard form of the equation of the circle is

where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have

<u>Convert to standard form</u>
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square twice. Remember to balance the equation by adding the same constants to each side.


Rewrite as perfect squares


the center of the circle is 
the radius of the circle is 
therefore
<u>the answer is</u>
the radius of the circle is 