Ask question

Ask question

All categories

3 years ago

10

If AB=29cm and angle A= 25 degrees, what is AC to the nearest centimeter

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

13.5

Step-by-step explanation:

Using sine rule

Tan25 = AC/AB = AC/29

AC = 29 × Tan 25 = 29 × 0.45 = 13.5229220865

You might be interested in

Beginning from a depth of 35 ft below the surface, a whale swims upward and jumps to a height of nearly 17 feet above the surfac

Shtirlitz [24]

Answer: there is a proplem in here

oi

Step-by-step explanation:

6 0

2 years ago

Hector is rewriting the expression 7 Superscript 11 in expanded form. How many terms will be multiplied in his rewritten express

-BARSIC- [3]

Answer:11

Step-by-step explanation:just took the quiz <3

3 0

3 years ago

Read 2 more answers

Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with mea

Anika [276]

Answer:

About 3 years Speedy Jet printers be guaranteed.

Step-by-step explanation:

Given : Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with

mean $\mu = 4$ and standard deviation $\sigma = 0.78$

If the company wishes to replace no more than 10% of the printers.

To find : How long should Speedy Jet printers be guaranteed ?

Solution :

Using Z- table,

Z value corresponding to 10% or 0.10 = -1.28.

Applying z-score formula,

$z=\frac{x-\mu}{\sigma}$

The value of x is given by,

$x=(z\times \sigma)+\mu$

Substitute the values,

$x=(-1.28\times 0.78)+4$

$x=-0.9984+4$

$x=3.0016$

So, approx 3 years.

Therefore, About 3 years Speedy Jet printers be guaranteed.

8 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

Please help:)!!! thanks sm

castortr0y [4]

The answer is 12 because I just did the math

6 0

3 years ago