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Over [174]
3 years ago
8

Name the following carboxylic

Chemistry
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

methylpentanoic acid,,,,,I guess so

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Anything with mass creates gravity, but the amount of gravity is proportional to the amount of mass.
gayaneshka [121]

Answer:

Explanation:

The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects. Gravity is a force that increases the velocity of falling objects - they accelerate.

6 0
4 years ago
Read 2 more answers
(b)
mixas84 [53]

Answer:

Group 18th

Explanation:

The group 18th of periodic table which is composed of Noble gases mainly was missing from the Mendeleev's periodic table. The reason for this is that Noble gases are least reactive, therefore, it was difficult to predict such elements which do not react with other elements.

4 0
4 years ago
Setting up a one-step unit conversion A student sets up the following equation to convert a measurement. (The ? stands for a num
Aneli [31]

Answer:

0.0008 m

Explanation:

We are given that 0.080 cm

We have to convert 0.080 cm into meter

To find the value of 0.080 cm in meter we are using unitary method

We know that

100 cm =1 m

1 cm =\frac{1}{100} m

Therefore, 0.080 cm =\frac{1}{100}\times 0.080 m

0.080 cm =\frac{1}{100}\times \frac{80}{1000}m

0.080 cm =\frac{8}{10000}m

0.08cm=0.0008 m

Hence, the value of 0.080 cm is equal to 0.0008 meter .

7 0
3 years ago
QUESTION 10
iris [78.8K]

Answer:

B

Explanation:

Phosphofructokinase-1

6 0
2 years ago
Consider the reaction:
goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

5 0
3 years ago
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