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Musya8 [376]
2 years ago
14

Calculate the concentration (in m) of hydroxide ions in a solution at 25. 0 °C with a poh of 3. 58.

Chemistry
1 answer:
Reika [66]2 years ago
3 0

The concentration (in M) of hydroxide ions in a solution at 25°C with a pOH of 3.58 is 2.6 × 10⁻⁴ M.

pOH is the measure of basic nature of a solution by evaluating the [OH⁻] concentration.

It is the negative logarithm of the hydroxide ion concentration.

Given,

pOH = 3.58

Temperature = 25°C = 298K

At 25°C, the relation of pOH and [OH⁻] concentration is as follows:

∴ pOH = -log [OH⁻]

⇒ 3.58 = -log [OH⁻]

⇒log [OH⁻] = -3.58

⇒ [OH⁻] = antilog (-3.58)

⇒[OH⁻] = 2.6 × 10⁻⁴ M

The concentration (in m) of hydroxide ions in a solution at 25.0 °C with a pOH of 3. 58 is 2.6 × 10⁻⁴ M.

Learn more about pOH here, brainly.com/question/17144456

#SPJ4

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B. 0.0291

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Explanation:

A.

Mass of KCl (solute): 28.0 g

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B.

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The total number of moles is 0.376 mol + 12.5 mol = 12.9 mol.

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C.

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D.

The molality of KCl is:

m = moles of KCl / kilograms of solvent

m = 0.376 mol / 0.225 kg

m = 1.67 m

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