I think glucose, not completely sure on this.
Answer:
i think its vestigial, but if not then it is homologous.
hope that hepls!
The reason should be denaturing of the active site of the enzyme.
The rate of the enzymic
reaction depends on pH, concentration of substrate, enzyme molecule
concentration and the temperature. With the increase of temperature, the rate
of the enzymic reaction also increases. But this only happens up to a
certain point. After a certain temperature, the rate becomes to
decrease and eventually will stop. This is because denaturing of the enzyme.
Although other factors are perfect, the high temperature causes to break down
of bond interactions and hence the active site will be changed. If
the active site of an enzyme changed, then substrate cannot bind with that enzyme
anymore.<span>
<span>The temperature which the rate of the reaction is
maximum is called optimum temperature and it normally around 40°C. This can be
varied from enzyme to enzyme</span></span>
You have already worked out that the white flower must have genotype pp (two recessive white alleles) and that the purple flower could be homozygous (PP) or heterozygous (Pp).
<span>Now you need to draw Punnet squares for both possibilities and show that the way to determine the genotype is the proportion of purple offspring. If the genotype is PP, then all the progeny will inherit one P and one p, making 100% purple flowers. If the purple flower is Pp, then half will inherit P and half will inherit p, making for half white and half purple flowers in the next generation.</span>
