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DiKsa [7]
3 years ago
14

-2/3×3/5+5/2-3/5×1/6​

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Yuki888 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

\frac{-2}{3}*\frac{3}{5}+\frac{5}{2}-\frac{3}{5}*\frac{1}{6}=\frac{-2}{5}+\frac{5}{2}-\frac{1}{5*2}\\\\= \frac{-2}{5}+\frac{5}{2}-\frac{1}{10}\\\\=\frac{-2*2}{5*2}+\frac{5*5}{2*5}-\frac{1}{10}\\\\=\frac{-4}{10}+\frac{25}{10}-\frac{1}{10}\\\\=\frac{-4+25-1}{10}\\\\=\frac{20}{10}\\\\= 2

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The angles of a triangle add up to 180 degrees.
Alex_Xolod [135]

Answer:

33°

Step-by-step explanation:

We were given that:

1- The angles of a triangle add up to 180 degrees

2- The second angle is 15 degrees larger than the smallest angle

3- The third angle is 3 times as big as the smallest angle

So, first of all, let's call the smallest angle x.

the second angle will be (x + 15°) since it is 15 degrees greater than the smallest angle

and the third will be 3x, since it is 3 times bigger than the smallest angle.

With the information we have, we can form an equation!

180° = x + (x+ 15°) + 3x

180° = 5x + 15°

180° - 15° = 5x + 15° - 15°

165° = 5x

165°/5 = 5x/5

33° = x

therefore, the smallest angle measures 33° degrees, the second angle measures 48° and the third angle measures 99°.

99° + 33° + 48° = 180°

so it is safe to say this answer is correct!

8 0
3 years ago
60<br>42<br>2V175 - 2V20-<br>+ 8/5<br>45<br>28​
iren [92.7K]

Answer: 100

Step-by-step explanation:

3 0
3 years ago
please answer of 6 of these but if you do then you get brainliest but answer all 6 and show the work on how to do it also for ea
zloy xaker [14]

5. r×2×pi

7km×2×pi=43.98km

6. d×pi

20cm×pi=62.83cm

7. d×pi

8.5m×pi=26.70m

8. r×2×pi

11yd×2×pi=69.12yd

9. d×pi

6(2/5)ft×pi=20.11ft

10. r×2×pi

25in×2×pi= 157.08in

7 0
2 years ago
Lucy wants to make different types of Cheesecake, each cheesecake uses 2/3 pound of cream cheese, she has 2 pounds of cream chee
Sveta_85 [38]
She can make 2 cheese cakes with the amount of cream cheese she has
6 0
3 years ago
A homogeneous second-order linear differential equation, two functions y1 and y2 , and a pair of initial conditions are given be
Basile [38]

Answer:

Step-by-step explanation:

Check part

y= C_1y_1 + C_2y_2 = C_1cos(7x)+C_2sin(7x)

y'= -7 C_1sin(7x)+7C_2cos(7x)

y"= -49 C_1cos(7x) - 49 C_2sin(7x)

Now, replace to the original one.

y"+49 y = -49C_1cos(7x)-49 C_2 sin(7x) + 49 C_1cos(7x) +49 C_2sin(7x) = 0\\

Done!!

Particular solution

y(0) = C_1cos(0) + C_2 sin(0) = C_1= 10

I believe that y'(0) = 4, not y(0) anymore. Since y(0) CANNOT have two different solution.

y(0)'= -7 C_1sin(0) + 7 C_2 cos (0) = 7 C_2= -4

C_2 = -4/7

The last step is to put C1, C2 into your solution. You finish it.

4 0
4 years ago
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