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IrinaVladis [17]
4 years ago
7

Explain how finding 4x384 can help you find 4x5384

Mathematics
1 answer:
yulyashka [42]4 years ago
5 0
Well the 384 part is the harder part because it is a more complex number (for humans) so after you find out what 4x384=(1536) then 4x5000 is simple and you just add the two answers together.
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Which of the following relations has an inverse that is not a function?
sertanlavr [38]

Answer:

Option B is correct.

The relation which has an inverse that is not a function is :(1, 2), (1, 3), (4, 3)

Step-by-step explanation:

Inverse of a function is the set of ordered pairs obtained by interchanging the first and second elements of each pair in the original function.

Let f(x) ={(1, 2), (1, 3), (4, 3)}

To find the inverse:

Inverse of f(x)=g(x)= {(2, 1), (3, 1), (3, 4)}

Function states that a relation in which each input value has only one output value.

Since, g(x) is not a function because the input 3 has multiple output values,.

Therefore, the only relation which has an inverse that is not a function is :(1, 2), (1, 3), (4, 3)



8 0
3 years ago
Solve the equation 2sin^2(x) = 1 for x ∈ [-π,π], expressing all solutions as exact values. please help its urgent !!
almond37 [142]

Answer:

2sin.2(x) sd s

Step-by-step explanation:

4 0
3 years ago
Wesley spent $34.60 at the grocery store. 15% of that was spent on fruit. How much did Wesley spend on fruit?
bagirrra123 [75]

Answer:

5.19 I'm not 100% sure if it's right tho.

6 0
3 years ago
Read 2 more answers
What is the probability of rolling a sum of 77 on a standard pair of six-sided dice? express your answer as a fraction or a deci
Ad libitum [116K]
0% because the highest number that you can get on a pair of dice is 12
7 0
3 years ago
Write the expression as either the sine, cosine, or tangent of a single angle. (2 points)
sattari [20]

Answer:

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(2π/15)

Step-by-step explanation:

We will make use of trig identities to solve this. Here are some common trig identities.

Cos (A + B) = cosAcosB – sinAsinB

Cos (A – B) = cosAcosB + sinAsinB

Sin (A + B) = sinAcosB + sinBcosA

Sin (A – B) = sinAcosB – sinBcosA

Given cos(π/3)cos(π/5) + sin(π/3)sin(π/5) if we let A = π/3 and B = π/5, it reduces to

cosAcosB + sinAsinB and we know that

cosAcosB + sinAsinB = cos(A – B). Therefore,

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(π/3 – π/5) = cos(2π/15)

8 0
3 years ago
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