Answer:

Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m ×
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 

55 is 55% of 100.
percents are based of of 100, so 55 would be 55/100 or 55%.
Answer:
Yumiko should multiply the other equation by 3.
If she adds the two equations she would be left with the variable 'x'.
Step-by-step explanation:
Given the two equations are as follows:


It is given that she multiplies the first equation by 6. Therefore, (1) becomes

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.
The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.
Therefore, Equation (2) becomes:

Now, we add Equation (a) and Equation (b).


Factor: 3
Equation: 27x = 126
8988989889 IDK hate doing the it but luv getting the answers
Answer:
x = 33.92.
Step-by-step explanation:
0.21 (3x + 3) + 4 = 26
Distribute the 0.21 over the parentheses:
0.63x + 0.63 = 22
0.63x = 22 - 0.63
0.63x = 21.37
x = 21.37 / 0.63
x = 33.92 (answer).