Answer:
5x-4y = -32
Step-by-step explanation:
First write the equation in point slope form
y-y1 = m(x-x1)
y - -2 = 5/4 ( x- -8)
y+2 = 5/4 (x+8)
Multiply each side by 4 to clear the fraction
4( y+2 )= 4*5/4 (x+8)
4y +8 = 5(x+8)
4y+8 = 5x+40
Subtract 4y from each side
8 = 5x-4y +40
Subtract 40 from each side
-32 = 5x-4y
5x-4y = -32
<h3>
Answer: 53%</h3>
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Explanation:
The question asks "What percent of females participate in extracurricular activities?" This means we only focus on the second column. There are 36 women, and of this total, 19 are in extracurricular activities.
Dividing the two values leads to approximately 19/36 = 0.52777 which rounds to 0.53
Then we move the decimal to the right two spots to get 53%
Roughly 53% of the female students participate in extracurricular activities.
Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
Hello there!
The only thing we have to do here is remember our trigonometric functions!
sin=y/r
cos=x/r
tan=y/x
sec=r/x
csc=r/y
cot=x/y
Knowing that tanᎾ=15/8, we know that y=15 and x=8
Now we need to look at the answer choices and see if they are correct.
A. secᎾ=17/8
Since secᎾ=r/x and r=17 and x=8, this is correct.
B. cosᎾ=15/17
Since cosᎾ=x/r and x=8 and r=17, this is wrong.
C. cotᎾ=8/15
Since cotᎾ=x/y and x=8 and y=15, this is also correct!
D. cscᎾ=17/15
Since cscᎾ=r/y and r=17 and y=15, this is right too.
I really hope this helps!
Best wishes :)
It is 21.73684210526316 which is rounded to the ones so it is 22.00000000000000
19x22=418 and 418 is close to 413 I help this help
