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Arada [10]
3 years ago
12

Given triangle ABC, if angle A = 40, a = 65, and angle B = 25. what is the length of b?

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

x=50

Step-by-step explanation:

40+65+25+x=180

Combine like terms

130+x=180

x=50

(triangles = 180)

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Can someone help me with this question, please. The problem is attached.
fomenos

It is a reflection across the y axis, then a translation to the right 2 units.  


I hope this helps!  If you have more you want help with I can help.  

3 0
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Preston is making cookies. He has fraction 4 over 5 cups of flour in a bag. He then used two fractions 1 over 10 cup scoops of f
maks197457 [2]
Step 1: 1/10 + 1/10 = 2/10

Step 2: 4/5 - 2/10
GCF: multiply both sides of 4/5 by 2 = 8/10

Step 3: 8/10 - 2-10 = 6/10

ANSWER: C <span>fraction 6 over 10, because fraction 4 over 5 minus 2 times fraction 1 over 10 equals fraction 4 over 5 minus fraction 2 over 10 </span>
8 0
4 years ago
Read 2 more answers
Prove diagonals of a rhombus are perpendicular
Lisa [10]

Answer:

A rhombus is a parallelogram with four congruent sides.

So, all sides of rhombus ABCD are congruent.

i.e, \overline{JM} \cong \overline{JK} \cong \overline{KL}\cong \overline{LM}

Also, we know that the diagonals of a parallelogram bisect each other.  

Since a rhombus is a parallelogram.

By property of rhombus , if point N is the intersection of the diagonals as shown in the figure, then

\overline{MN} \cong \overline{NK}         .....[1]

\overline{JN} \cong \overline{NL}

In ΔJNM and ΔJNK

\overline{MN} \cong \overline{NK}     [side]    [by (1)]

\overline{JM} \cong \overline{JK}     [side]          [Given]

By reflexive property states that a segment is congruent to itself:

\overline{JN} \cong \overline{JN}   [Side]                 [Reflexive Property]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

then by SSS congruence,

\triangle JNM \cong \triangle JNK

By CPCT [Corresponding Part of congruent triangles are congruent]

Since, JNM and JNK are corresponding angles therefore,

\angle JNM \cong JNK

Linear pair theorem states that two angles that form a linear pair are supplementary.

By linear pair theorem, JNM and JNK are supplementary

this mean:

m\angle JNM +m\angle JNK =180^{\circ}

Since, the angles are congruent i.e, \angle JNM \cong JNK

so;

m\angle JNK +m\angle JNK =180^{\circ}

or

m\angle JNK +m\angle JNK =180^{\circ}

2m\angle JNK=180^{\circ}

Simplify:

m\angle JNK =90^{\circ}

also; m\angle JNM =90^{\circ}

therefore, the diagonals of JKLM are perpendicular to each other i,e \overline{JL} \perp \overline{MK}


4 0
3 years ago
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