Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
324 feet
Step-by-step explanation:
h(3) = 16(3)^2 + 180
h(3) = 16(9) + 180
h(3) = 144 + 180
h(3) = 324
Answer:
Total cost = 983.8
Step-by-step explanation:
Monthly charge = 39.95
One time set up fee = x
Number of months = y
Total cost = x + 39.95y
The total cost of 6 months of service is 264.70.
264.70 = x + 39.95(6)
264.70 = x + 239.7
264.70 - 239.7 = x
x = 25
Total cost = 25 + 39.95y
Write and solve a linear equation to find the total cost for 2 years of service
2 years = 24 months
Total cost = 25 + 39.95y
= 25 + 39.95(24)
= 25 + 958.8
= 983.8
Total cost = 983.8
