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3 years ago

If a cube shaped box has a volume of 512 cm^3 if the box was filled with 1 cubic cm how many blocks make up each layer

Mathematics

1 answer:

bixtya [17]3 years ago

7 0

Answer:

MAYBE 12

Step-by-step explanation:

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Please help will mark brainliest

asambeis [7]

The total cost of the tent is 409.86

------------------------------------------------------

explanation:

230×0.65=149.50

230+149.50=379.50×.08=30.36

379.50+30.36=409.86

(Hope this helps :) )

5 0

2 years ago

Read 2 more answers

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

3 years ago

Simplify (x - y + 1) - (x + y - 1)

andrey2020 [161]

First, distribute the minus sign across the second set. So you have:

x - y + 1 - x - y + 1

Now, we combine like terms:
x-x=0
-y-y=-2y
1+1=2

So we have -2y+2

Hope that helps.

5 0

3 years ago

Where is the answer to the expression 4 − 8 located on a horizontal number line?

Lady_Fox [76]

Answer:

8 units to the left of 4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The area of a rectangular trampoline is 135 ft. The length of the trampoline is 6 ft

sammy [17]

Step-by-step explanation:

let width be x

length = 6+x

x times 6+x=135

2x+6=135

2x=135-6

129/2=x

64.5

4 0

3 years ago