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Marat540 [252]
2 years ago
7

Select the correct answer. Which sentence correctly compares temperatures?

Mathematics
2 answers:
Ad libitum [116K]2 years ago
5 0

Answer: C

Step-by-step explanation:

C is the only statement that is correct

it's all based on negative numbers :)

SashulF [63]2 years ago
4 0
I believe the answer is C.
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Graph the solution of 2 ≥ 4 - v
Lerok [7]
For this case we have the following inequality:
 2 ≥ 4 - v
 The first thing we must do in this case is to clear the value of v.
 We have then:
 v ≥ 4 - 2
 v ≥ 2
 Therefore, the solution set is given by:
 [2, inf)
 Answer:
 
See attached image.

6 0
3 years ago
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25 cm of ribbon at £2.20 per metre what is the cost
Step2247 [10]
0.55 pence or quid per 25 centimeters as if you multiply it by 4 it would be 2.20 pound because 1 metre is 100 centimeters after i divide 100 by 25 i get 4 which would be 1/4 which i would then multiply 1/4 x 2.2 pound 
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3 years ago
10 burgers cost $600 what is the cost of 1 burger and what will 15 burgers cost​
attashe74 [19]

Answer:

The cost of 1 burger is $60 (600 ÷ 10)

The cost of 15 burgers is 900 (15 x 60)

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3 years ago
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Tell whether the following set is an empty set or not.
Liono4ka [1.6K]

Answer:

It is not an empty set

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible.

A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.

Let’s say three angles are measuring 91 degrees in a quadrilateral.

91 + 91 + 91 + x = 360

x = 87

The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.

7 0
3 years ago
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Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
Vlad [161]

Answer

P(A) = 0.30

P(B) = 0.77

P(A\ n\ B) = 0.22

P(A\ u\ B) = 0.85

Explanation:

Given

See attachment for proper data presentation

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

Yes = 22 and No = 8

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

P(A) = 0.30

Solving (b): P(B)

We only consider data in the Yes column.

Here:

(1) = 22    (2) = 25 and (3) = 30

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

P(B) = 0.77

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

P(A\ n\ B) = 0.22

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

P(A\ u\ B) = 0.85

7 0
2 years ago
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