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2 years ago

What happens to the particles in iodine when you increase

Mathematics

1 answer:

Tju [1.3M]2 years ago

5 0

Answer:

When you have iodine gas at 200 degrees, the temperature and thus pressure as so high, that when cooling down you enter the liquid phase. And when some of this gas then condenses, the pressure drops. So the remaining part of the gas can sublime.

Step-by-step explanation:

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5(2x+6)=-4(-5-2x)+3x step by step

Oksi-84 [34.3K]

Answer:

x = 10

Step-by-step explanation:

Okay, let's solve :)

So first we have to distribute on the left side(it doesn't matter which side FYI)

When we do, we have :

10x + 30 = -4(-5-2x)

Now we distribute on the right side! Remember, negative * negative = positive.

10x + 30 = 20 + 8x + 3x

Let's simplify on the right side to

10x + 30 = 20 + 11x

Now, let's subtract 10x on both sides to get

x + 20 = 30(i simply flipped the equation)

Subtract 20 on both sides to get!

x = 10!

5 0

3 years ago

Combine the like terms to create an equivalent expression,

evablogger [386]

Answer: 2y+6

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Solve for X. <br><br> <img src="https://tex.z-dn.net/?f=log_%7B8%7D%20x-log_%7B8%7D%20%28-2x%2B4%29%20%3D%20log_%7B8%7D%203" id=

taurus [48]

Answer: $x=\frac{12}{7}$

Step-by-step explanation:

Remember the logarithms properties:

$log(m)-log(n)=log(\frac{m}{n})\\\\b^{log_b(a)}=a$

Then,simplifying:

$log_{8}(\frac{x}{-2x+4}) = log_{8}(3)$

Apply base 8 to boths sides and then solve for "x":

$8^{log_{8}(\frac{x}{-2x+4})}=8^{log_{8}(3)}\\\\\frac{x}{-2x+4}=3\\\\x=3(-2x+4)\\\\x=-6x+12\\x+6x=12\\7x=12\\\\x=\frac{12}{7}$

4 0

3 years ago

Read 2 more answers

The first side of a triangle measures 3 in. less than the second side, the third side is 2 in. more than the first side, and the

Debora [2.8K]

Answer:

P = 3x - 4

Step-by-step explanation:

Side 1 = x - 3

Side 2 = x

Side 3 = 2 + (Side 1) = 2 + x - 3 = x - 1

Perimeter = 20 in

Perimeter = Side 1 + Side 2 + Side 3

Perimeter = (x - 3) + (x) + (x - 1)

Perimeter = x - 3 + x + x - 1

Perimeter = 3x - 3 - 1

Perimeter = 3x - 4

P = 3x - 4

5 0

3 years ago

Find the volume of the solid of revolution generated by revolving the region bounded by y = 2x^2, y = 0, and x = 2 about the x-a

Irina18 [472]

Answer:

$128 \pi/5 units^3$

Step-by-step explanation:

The volume of the solid revolution is expressed as;

$V = \int\limits^2_0 {\pi y^2} \, dx$

Given y = 2x²

y² = (2x²)²

y² = 4x⁴

Substitute into the formula

$V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\$

Substituting the limits

$V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3$

Hence the volume of the solid is $128 \pi/5 units^3$

5 0

2 years ago