Answer:
The equations shows a difference of squares are:
<u>10y²- 4x²</u> $ <u>6y²- x²</u>
Step-by-step explanation:
the difference of two squares is a squared number subtracted from another squared number, it has the general from Ax² - By²
We will check the options to find which shows a difference of squares.
1) 10y²- 4x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√10 y + 2x )( √10 y - 2x)
2) 6y²- x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√6y + x )( √6y - x)
3) 8x²−40x+25
The expression is not similar to the general form, so the equation does not represent a difference of squares.
4) 64x²-48x+9
The expression is not similar to the general form, so the equation does not represent a difference of squares.
Answer:
25
Step-by-step explanation:
From the given information;
Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.
= 1000x
Thus, the required number of hours it will take can be computed as:

cost per hour = 125
If each plate costs $20 to make, then the total number of plate will equal to 40x
∴
The total cost can be computed as:


At C'(x) = 0




x = 25


where; x = 25

C''(x) = 1.6
Thus, at x = 25, C'' > 0
As such, to minimize the cost, the printer needs to make 25 metal plates.
The first answer is 80, and the second answer is still 65.5. Hope this helps!
Step-by-step explanation:
The question is wrong. The correct equation is :

We know that the equation gives the relation between temperature readings in Celsius and Fahrenheit.
Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.
So for the incise (a) we answer Yes, C is a function of F.
For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.
Dom (C) = ( - ∞ , + ∞)
For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.
Therefore the range will be
Rang (C) = (0,100)
Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :
For C = 0 :
⇒ 
And for C = 100 :
⇒ 
Therefore, the domain as relating temperatures of water in its liquid state is
Dom (C) = (32,212)
For (d) we only need to replace in the equation by
and find the value of C ⇒
⇒

≅ 21.67
C(71) = 21.67 °C