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mote1985 [20]
3 years ago
13

A chef is going to use a mixture two different brands of Italian dressing the first spring and days 5% vinegar the second brain

contains 15% vinegar the sheriff wants to make 390$ ml addressing that is 9% vinegar how much of each brand should she use
Mathematics
1 answer:
Temka [501]3 years ago
7 0

I guess the chef is making the mixture for the sheriff... Let <em>x</em> be the amount of dressing with 5% vinegar that is required, and <em>y</em> the amount of 15% vinegar dressing (both amounts in mL).

The sheriff wants 390 mL of the mixed dressing, so that

<em>x</em> + <em>y</em> = 390

<em>x</em> mL of the 5% dressing contains 0.05<em>x</em> mL of vinegar, while <em>y</em> mL of the 15% dressing contains 0.15<em>y</em> mL of vinegar. The resulting mixture should have a concentration of 9% vinegar, so that it contains 0.09 (390 mL) = 35.1 mL of vinegar. This means

0.05<em>x</em> + 0.15<em>y</em> = 35.1

Solve for <em>x</em> and <em>y</em> :

<em>y</em> = 390 - <em>x</em>

0.05<em>x</em> + 0.15 (390 - <em>x</em>) = 35.1

0.05<em>x</em> + 58.5 - 0.15<em>x</em> = 35.1

23.4 = 0.10<em>x</em>

<em>x</em> = 234

<em>y</em> = 156

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Molly earns a rebate each month on her movie tickets and books. She earns $0.25 for each movie ticket and $2 for each book. Last
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6 0
3 years ago
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How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At
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Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

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Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

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Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

  \rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}

             

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4 years ago
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