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ella [17]
2 years ago
15

Find the surface area of the cube shown below. units 2 2 squared

Mathematics
1 answer:
ruslelena [56]2 years ago
7 0

The surface area of the cube with a side length of 2 units is 24 units squared

<h3>How to determine the surface area?</h3>

The side length of the cube is given as:

l = 2

The surface area is calculated as:

Surface area = 6l^2

This gives

Surface area = 6 *2^2

Evaluate

Surface area = 24

Hence, the surface area of the cube is 24 unit squared

Read more about surface area at:

brainly.com/question/13175744

#SPJ1

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Find the value of x<br> 85<br> (X + 37)<br> (6x + 22)<br> 69
g100num [7]

Answer:

<u>x </u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u>

<u>The </u><u>angles </u><u>of </u><u>the </u><u>quadrilateral</u><u> </u><u>are:</u>

  • <u>8</u><u>5</u><u>°</u>
  • <u>5</u><u>8</u><u>°</u>
  • <u>1</u><u>4</u><u>8</u><u>°</u>
  • <u>6</u><u>9</u><u>°</u>

Step-by-step explaination:

The above figure is a quadrilateral.

Hence, the angle sum of the shape is 360°.

Therefore,

85 + (x + 37) +69 + (6x + 22) = 360

85 + x + 37 + 69 + 6x + 22 = 360

(85 + 37 + 69 + 22) + (x + 6x) = 360

213 + 7x = 360

7x = 360 -  213

7x = 147

x =  \frac{147}{7}

x = 21

4 0
2 years ago
What is the inverse of the function H(x)=3/4x+12
Mrac [35]

Answer:

h^{-1}(x) = \frac{4x-48}{3}

Step-by-step explanation:

let y = h(x) and rearrange making x the subject, that is

y = \frac{3}{4} x + 12 ( multiply through by 4 to clear the fraction )

4y = 3x + 48 ( subtract 48 from both sides )

4y - 48 = 3x ( divide both sides by 3 )

\frac{4y-48}{3} = x

Change y back into terms of x, thus

h^{-1} (x) = \frac{4x-48}{3}

3 0
4 years ago
Point B is 2/3 the way from A(-2,5)to C(4,-4). Find the location of B
mr Goodwill [35]

well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.

\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill

\bf \stackrel{~\hfill \textit{coordinates to be added to point A}} {\cfrac{2}{3}(6,-9)\implies \cfrac{2}{3}(6)~,~\cfrac{2}{3}(-9)\qquad \implies \qquad \left(4,-6\right)} \\\\\\ \stackrel{\textit{additions to point A}} {\stackrel{\textit{point A}}{(-2,5)}+\left( 4,-6\right)}\implies \left( -2+4~~,~~5-6\right) = B\implies (2~,~-1)=B

5 0
3 years ago
A patient has been ordered 750 mg/day of medication that is available in tablets of 75mg each. The nurse will administer a dosag
soldi70 [24.7K]

Answer:

The last dose will be administered at 6 P.M.

Step-by-step explanation:

This problem can be solved by direct rule of three.

The problem states that each tablet has 75mg of medication, and that every 3 hours, 2 tablets are administered.

So

1 tablet - 75mg of medication

2 tabets - xmg of medication

x = 150mg

It means that in each dose, 150mg of medication are administed.

At 6am, as the first dose is administered, the patient will have taken 150mg of medication. In how many doses will the patient have been administed 750mg?

1 dose - 150mg

x doses - 750mg

150x = 750

x = 5 doses.

The doses are administed in intervals of 3 hours. After the first dose, there will be 4 doses remaining. So it will take 4*3 = 12 hours to administer 4 doses.

So, if the first dose is administed at 6am, the last is going to be administed at 6h+12h = 18h = 6P.M.

5 0
3 years ago
How can you graph m(x)=5x and then compare it to f(x)=x?
erastovalidia [21]
Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.
5 0
4 years ago
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