Answer:
<u>x </u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u>
<u>The </u><u>angles </u><u>of </u><u>the </u><u>quadrilateral</u><u> </u><u>are:</u>
- <u>8</u><u>5</u><u>°</u>
- <u>5</u><u>8</u><u>°</u>
- <u>1</u><u>4</u><u>8</u><u>°</u>
- <u>6</u><u>9</u><u>°</u>
Step-by-step explaination:
The above figure is a quadrilateral.
Hence, the angle sum of the shape is 360°.
Therefore,








Answer:
(x) = 
Step-by-step explanation:
let y = h(x) and rearrange making x the subject, that is
y =
x + 12 ( multiply through by 4 to clear the fraction )
4y = 3x + 48 ( subtract 48 from both sides )
4y - 48 = 3x ( divide both sides by 3 )
= x
Change y back into terms of x, thus
(x) = 
well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.
![\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Binternal%20division%20of%20a%20segment%20using%20a%20fraction%7D%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B-2%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-4%7D%29~%5Chfill%20%5Cfrac%7B2%7D%7B3%7D%5Ctextit%7B%20of%20the%20way%20from%20%7DA%5Cto%20C%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_2%7D%7B4%7D-%5Cstackrel%7Bx_1%7D%7B%28-2%29%7D%2C%20%5Cstackrel%7By_2%7D%7B-4%7D-%5Cstackrel%7By_1%7D%7B5%7D%29%5Cimplies%20%284%2B2%2C-9%29%20%5Cstackrel%7B%5Ctextit%7Bcomponent%20form%20of%20segment%20AC%7D%7D%7B%5Cqquad%20%5Cimplies%20%5Cqquad%20%286%2C-9%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
The last dose will be administered at 6 P.M.
Step-by-step explanation:
This problem can be solved by direct rule of three.
The problem states that each tablet has 75mg of medication, and that every 3 hours, 2 tablets are administered.
So
1 tablet - 75mg of medication
2 tabets - xmg of medication
x = 150mg
It means that in each dose, 150mg of medication are administed.
At 6am, as the first dose is administered, the patient will have taken 150mg of medication. In how many doses will the patient have been administed 750mg?
1 dose - 150mg
x doses - 750mg
150x = 750
x = 5 doses.
The doses are administed in intervals of 3 hours. After the first dose, there will be 4 doses remaining. So it will take 4*3 = 12 hours to administer 4 doses.
So, if the first dose is administed at 6am, the last is going to be administed at 6h+12h = 18h = 6P.M.
Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.