Using trigonometric ratio, the height of the ground above the ground to the nearest hundredth is 44.85 ft
The situation forms a right angle triangle.
<h3>What is a right angle triangle?</h3>
Right angle triangle has one of its angles as 90 degrees. The sides and angles can be found using trigonometric ratios.
Therefore, the length of the string is the hypotenuse side of the triangle formed . The opposite side of the triangle is the height of the kite form the ground.
Therefore, the height of the kite form the ground can be found as follows;
sin 33° = opposite / hypotenuse
sin 33° = h / 75
cross multiply
h = 75 × sin 33
h = 40.8479276261
h = 40.84
The height of kite from ground = 40.847 + 3.5 = 44.3479276261 = 44.85 ft
learn more on right triangles here: brainly.com/question/25799394
Solving for the polynomial function of least degree with
integral coefficients whose zeros are -5, 3i
We have:
x = -5
Then x + 5 = 0
Therefore one of the factors of the polynomial function is
(x + 5)
Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0
Therefore one of the factors of the polynomial function is (x^2
+ 9)
The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)
= x^3 + 9x + 5x^2 = 45
Therefore, x^3 + 5x^2 + 9x – 45 = 0
f(x) = x^3 + 5x^2 + 9x – 45
The polynomial function of least degree with integral coefficients
that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45
(2,3)(4,4)
slope(m) = (4-3) / (4-2) = 1/2
y = mx + b
slope(m) = 1/2
(4,4)...x = 4 and y = 4
now we sub
4 = 1/2(4) + b
4 = 2 + b
4 - 2 = b
2 = b
equation is : y = 1/2x + 2
Nine wholes with five twelves
9 5/12
