All categories

3 years ago

(x2 − 8x + 5) − (−3x2 + 5x − 9)

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

(X²-8X+5)-(-3X²+5X-9)
=X²-8X+5+3X²-5X+9
=4X²-13X+14
That's your answer lovely~

You might be interested in

List the first six common multiples of 6 and 9

V125BC [204]

Answer:

The first few multiples of 6 and 9 are (6, 12, 18, 24, 30, . . . ) and (9, 18, 27, 36, . . . )

3 0

2 years ago

A boat leaves a dock and travels 9 miles due north and 12 miles due west. Find how far the boat is from the dock. Type the corre

adelina 88 [10]

Answer:

15 miles

Step-by-step explanation:

Let's say the dock is at the origin on a coordinate plane and each unit is 1 mile. If the boat travels 9 mile due north, that means that we move up from the origin (0, 0) 9 units to point A (0, 9). Now, this boat moves 12 miles due west, so we will go 12 units to the left of (0, 9) to point B (-12, 9). See the attached drawing (sorry for the crudeness).

Notice that this is a right triangle with legs of 9 and 12. That means the distance from the boat to the dock is just the hypotenuse, so use the Pythagorean Theorem: distance = $\sqrt{9^2+12^2} =\sqrt{81+144} =\sqrt{225} =15$

Thus, the answer is 15 miles.

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is the vertex of the absolute value function defined by ƒ(x) = |x + 2| + 4?

Marrrta [24]

Answer:

C. (-2,4)

Step-by-step explanation:

We have been given a function $f(x)=|x+2|+4$ and we are asked to find the vertex of our absolute value function.

The rules for the translation of a function are as follows:

$f|x-h|=\text{Graph shifted to right by h units}$

$f|x+h|=\text{ Graph shifted to left by h units}$

$f|x|+h=\text{ Graph shifted upward by h units}$

$f|x|-h=\text{ Graph shifted down by h units}$

Upon comparing our absolute function with above transformations we can see that our function is shifted to two units right of the origin(0,0) so x coordinate of our absolute function will be -2.

Our function is shifted upward from origin by 4 units, therefore, y-coordinate of our absolute value function will be 4.

$f(x)=|x--2|+4$

Therefore, the vertex of our absolute value function will be on point (-2,4) and option C is the correct choice.

4 0

3 years ago

Read 2 more answers

Given that u =< 2,12 >, and z =< -7,5 >

swat32

Using the dot product:

For any vector x, we have

||x|| = √(x • x)

This means that

||w|| = √(w • w)

… = √((u + z) • (u + z))

… = √((u • u) + (u • z) + (z • u) + (z • z))

… = √(||u||² + 2 (u • z) + ||z||²)

We have

u = ⟨2, 12⟩ ⇒ ||u|| = √(2² + 12²) = 2√37

z = ⟨-7, 5⟩ ⇒ ||z|| = √((-7)² + 5²) = √74

u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46

and so

||w|| = √((2√37)² + 2•46 + (√74)²)

… = √(4•37 + 2•46 + 74)

… = √314 ≈ 17.720

Alternatively, without mentioning the dot product,

w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩

and so

||w|| = √((-5)² + 17²) = √314 ≈ 17.720

7 0

2 years ago

What are the challenges of similar triangles?

Lady bird [3.3K]

Answer:

There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.

Step-by-step explanation:

6 0

3 years ago