Lets set the two numbers as 'a' and 'b'
Now let us set up some equations based on the information:
- sum of two numbers 49 --> a + b = 49
- difference of the two numbers is 15 --> a -b =15
Equations
a + b = 49 -- equation 1
a - b = 15 -- equation 2
Solve:
(equation 1) + (equation 2)
2a = 64
a = 32 -- equation 3
(equation 3)'s value of a into (equation 2)
32 - b = 15
b = 17
The products of 'a' and 'b' is 544
Hope that helps!
Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
As a fraction, 54% is 27/50.
Answer:
1) <2 ; 60
2) <3 ; 60
3) <4 and <3. <4 = 120 and <3 = 60
4) <1, <3, and <4 = 125. <2 = 55
Step-by-step explanation:
1)
Corresponding angles are equal
2)
Alternate interior angles are equal
3)
<4 and <3 are same-side interior angles. This makes them supplementary angles
<4 = 120
<3 = 60
4)
<1 = <4 = <3. All of these angles equal 125.
<2 + <1 = 180
<2 + 125 = 180
<2 = 55
Answer:
x = 4
, y = 6
Step-by-step explanation:
Solve the following system:
{x + 3 y = 22 | (equation 1)
2 x - y = 2 | (equation 2)
Swap equation 1 with equation 2:
{2 x - y = 2 | (equation 1)
x + 3 y = 22 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x - y = 2 | (equation 1)
0 x+(7 y)/2 = 21 | (equation 2)
Multiply equation 2 by 2/7:
{2 x - y = 2 | (equation 1)
0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{2 x+0 y = 8 | (equation 1)
0 x+y = 6 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 4
, y = 6
