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3 years ago

Simplify this expression

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

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3 years ago

Action movies make up 85% of Devon’s movie collection. If he has 20 movies, how many action movies are in Devon’s collection ? E

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3 years ago

Read 2 more answers

I give brainlilset nxgbkj,m.d/ed<br> q

ra1l [238]

Hello,

First take both prisms and multiply them. Then subtract A-B=?

Workspace:

A= 20*9*9=1620 in

B=11*5*9=295 in

1620-295= 1325.5 in

The correct answer is H) 1325.5 in

Hope this helps!!
Brainliest?

5 0

3 years ago

How to do this question plz

hjlf

Answer:

$\underline{ \boxed{ \underline{part \: a}}}. \\the \: required \: distance \: a part \: be \to \: \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \boxed{ \underline{324 }\degree }$

Step-by-step explanation:

$\underline{ \boxed{ \underline{part \: a}}}. \\ l et \: the \: required \: distance \: apart \: be \to \: \boxed{ \overline {p}} \\ let \: \boxed{ \angle \: P} \: be \: the \: angle \: of \: seperation \: between \: both \: ships :given \: by \to \\ P = (244 - 180) - (196 - 180 )= (64 -16) = \boxed{48 \degree} \\ if \: ship \: A \: and \: B \: left \: the \: port\: at \: (10:30) \: \\ then \: at \: (14 :00) \: their \: time \: interval \: would \: be \to \\ (14 : 00) - (10 : 30) = \boxed{ 3.5 \: hrs} \\ ship \: \boxed{A }\: distance \: from \: the \: port =( v \times t) = (30 \times 3.5) = \boxed{105 \: km} \\ ship \: \boxed{B }\: distance \: from \: the \: port =( v \times t) = (24 \times 3.5) = \boxed{84\: km} \\n ow........we \: cant \: do \: much \: if \: their \: are \: no \: angles \: to \: work \: with \to \\ applying \:t he \: cosine \: rule : we \: have \to \\ \cos(P) = \frac{ {a}^{2} + {b}^{2} - \overline{{p}^{2} } }{2(ab)} \\ {a}^{2} + {b}^{2} - \overline{{p}^{2} } = 2(ab) \cos(P) \\ \overline{{p}^{2} } = {a}^{2} + {b}^{2} - \{2(ab) \cos(P) \} \\ \overline{{p}^{2} } = {84}^{2} + {105}^{2} - \{2(84)(105) \cos(48 \degree) \} \\\overline{{p}^{2} } = 18,081 - 11,803.463897 \\ \overline{{p}^{2} } = 6,277.536103 \\ \overline{p } = \sqrt{6,277.536103} \\ \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ to \: sove \: this : we \: first \: find \: angle \: \angle \: B : by \: applying \to \\ \frac{ \sin(B) }{b} = \frac{ \sin(P) }{p} \\ p \ast \sin(B) = b \ast \sin(P) \\ B = \sin {}^{ - 1} ( \frac{ b \ast \sin(P)}{p} ) \\ B = \sin {}^{ - 1} ( \frac{ 105 \times \sin(48 \degree)}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} ( \frac{ 78.030206678}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} (0.9848455971) \\ \boxed{B = 80 \degree} \\ hence \ : the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \\ 360 - \{180 - (80 + 48 + 16) \} \\ 360 -(180 - 144 )\\ 360 -36 = \boxed{324 \degree }$

♨Rage♨

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3 years ago

what is the standart dievation of 63 and 37 and what is the standart dievation of 88 and 112 this is a sample not a population

PilotLPTM [1.2K]

Answer:

https://www.calculators.org/math/standard-deviation.php

Step-by-step explanation:

you can calculate standard deviation from here with proper working plus accurate results.

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3 years ago