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SOVA2 [1]
3 years ago
6

What is the perimeter of the triangle?

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0
We can count the bottom units to get 10 units. Now to get the sides of it.

Let’s split this triangle in the middle to get two right triangles.

The height of the triangle is 12 units and one of the legs is 5 ( from 10/2 )

Let’s find the hypotenuse

(5) ^2 + (12) ^2 = c^2

C = 13

So this mean each side is 13 units

13 + 13 + 10 = 36 units

Perimeter = 36 units

Stolb23 [73]3 years ago
7 0

Answer:

Step-by-step explanation:

5,9,8

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Answer:

yes

Step-by-step explanation:

4 0
4 years ago
Which ordered pair is a solution of the inequalty y&lt;3x + 1?
alexandr1967 [171]

Step-by-step explanation:

Since (-3) < 3(1) + 1 is true, option C is correct.

5 0
3 years ago
Line A is represented by the following equation: x + y = 2
Orlov [11]

Answer:

ax+ay=k; a\ne0, k\ne2a; line D in the options.

Step-by-step explanation:

The set of equations has no solutions if the two lines are parallel. A quick way to create a parallel line is to solve for y, put it in slope-intercept form. Else, as long as the cofficient of x and y are in the same ratio (in this case 1:1), the two lines are parallel, you just have to be careful not to pick the same line again!

The condition a\ne 0 makes sure you are still getting lines (else you would get rid of both x and y); the condition k\ne 2a makes sure you're not picking line A again, just written in a different form.

Now that we have the options:

A and C have a different ratio for the coefficient of x and y (2:1 and 1:2) so are not good.

Choice B is just a more complicated way to write the same line, you can see by dividing both sides by 2 and get back x+y=2.

Line D is correct.

3 0
3 years ago
Find the extreme values of f subject to both constraints. (if an answer does not exist, enter dne.) f(x, y, z) = x + 2y; x + y +
Mariana [72]
Using the method of Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda_1,\lambda_2)=x+2y+\lambda_1(x+y+z-4)+\lambda_2(y^2+z^2-4)

with partial derivatives (set equal to 0)

L_x=1+\lambda_1=0\implies\lambda_1=-1
L_y=2+\lambda_1+2\lambda_2y=0\implies\lambda_2y=-\dfrac12
L_z=\lambda_1+2\lambda_2z=0\implies\lambda_2z=\dfrac12
L_{\lambda_1}=x+y+z-4=0
L_{\lambda_2}=y^2+z^2-4=0

From L_y and L_z, we find that \lambda_2y=-\lambda_2z\implies y=-z. Then substituting into L_{\lambda_2}, we find

y^2+z^2=4\implies2y^2=4\implies y=\pm\sqrt2\implies z=\mp\sqrt2

and substituting these into L_{\lambda_1}, we get

x+y+z=4\implies x=4

So we have two possible critical points, (4,\pm\sqrt2,\mp\sqrt2), which give extreme values of 4+2\sqrt2 and 4-2\sqrt2, respectively.
5 0
3 years ago
The length of a kitten on a scale drawing is 8cm. If the scale is 1 cm:6cm, what is the actual length of the kitten?
drek231 [11]
The answer is 48, and i love the kitten reference! hope it helps!
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3 years ago
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