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UkoKoshka [18]
3 years ago
8

Properties of Triangles 2.0 (Math pleaseee help)

Mathematics
1 answer:
Arada [10]3 years ago
4 0

Answer:

The awncer is 6.0

Step-by-step explanation:

20.20.30.305.030.4

40.04.3.2.

40.54.

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Anna baked
Hitman42 [59]

Answer:

expression for cookies  Anna have 3c- 8

Step-by-step explanation:

Given:

Number of cookie batches Anna baked = 2

Number of cookies in each batch = c

Number of cookies Anna ate  = 8

To Find:

An expression representing the number of cookies left with Anna

Solution:

Let the expression representing the number of cookies left with Anna be y

First let us find the total number of cookies Anna baked

She baked 3 batches of cookies and each batch had c cookies in it

So,

Total number of cookies Anna baked =  number batches X Number of cookies in each batch

=>3 \times c

=> 3c

Now Anna ate 8 from 3c cookies, so she will be left with

=>3c-8 cookies

So , y = 3c- 8

5 0
4 years ago
Heloppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
babunello [35]

Answer:

2145

Explain:

1. 2500+1225=3725

2. 5870-3725=2145

5 0
3 years ago
Simplify this problem
garik1379 [7]
Omg what grade are you in. wish I could help.
4 0
4 years ago
What is another way to describe 45 is it 45 tens 0 ones 9 tens 5 ones or 4 tens 5 ones
denis-greek [22]

Answer:

4 tens and 5ones

Step-by-step explanation:

there is a four in the tens place making it 40 and 5 in the ones place making it 45

8 0
3 years ago
Read 2 more answers
Identify the equation of the parent function y=x^3 that is horizontally streched by a factor of 1/5 and reflected over the y axi
choli [55]

Answer:

y=\frac{-x^{3}}{125}

Step-by-step explanation:

As we know that,

<em>'Horizontal stretch, stretches the function left or right on the x-axis'. </em>

The general form of horizontal stretch is given by 'f(kx)', where 0<k<1 is the factor by which function is stretched horizontally.

Since, the function y=x^{3} which is stretched by a factor of \frac{1}{5}.

The new function is y=(\frac{x}{5})^{3} i.e. y=\frac{x^{3}}{125}.

<em>Further, the function is reflected over y-axis.</em>

That is, the reflected function is y=\frac{(-x)^{3}}{125} i.e. y=\frac{-x^{3}}{125}.

Hence, the required function is y=\frac{-x^{3}}{125}.

7 0
3 years ago
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