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inysia [295]
4 years ago
11

A jar contains 3 chocolate cookies, 5 peanut butter cookies, and 6 coconut cookies. If 3 cookies are selected in succession, wha

t is the probability of selecting chocolate, then peanut butter, and then coconut cookies, if replacement occurs each time?
Mathematics
1 answer:
tangare [24]4 years ago
3 0
3/14 because 3 chocolate cookies and 14 cookies in total so 3 out of 14 are chocolate
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rasheed needs to save $231 to earn money he plans to wash cars and charge $12 per car write to estimates rasheed could use to de
prisoha [69]
He would have to wash 20 cars at first i got 19.25 because i divided 231 by 12 but i rounded up to 20 just to be safe....
6 0
4 years ago
Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
Aleonysh [2.5K]

Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

5 0
4 years ago
Read 2 more answers
Use the Distributive Property to solve the equation. −3​(x+5​)=9.
Arisa [49]
−3 (x+5 ) = 9.
-3(x) + -3(5) = 9
-3x -15 = 9
+15 +15
-3x = 24
/-3 -3
x = -8 Hope this helps!
7 0
3 years ago
Read 2 more answers
A circle has a circumference of 6 cm. Find the diameter of the circle.
Mariulka [41]

Answer:

d≈1.91cm

Step-by-step explanation:

7 0
3 years ago
Distribute and simplify the radicals below
nlexa [21]

Answer:

i think A is answer you should to do

3 0
3 years ago
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